You would need a pen & paper to solve this riddle.
Solve the given equations and find the value of E.
If;
A x 4 = E
B / 4 = E
C + 4 = E
D – 4 = E
A + B + C + D = 100
Then;
E = ?

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We have the following information;
A x 4 = E
B / 4 = E
C + 4 = E
D – 4 = E
A + B + C + D = 100
Let\’s write the first 4 equations in terms of E.
A = E/4
B = 4E
C = E – 4
D = E + 4
Let\’s put this value in A + B + C + D = 100; we get,
E/4 + 4E +(E – 4) + (E + 4) = 100;
Solving this euqations;
E/4 + 4E + E – 4 + E + 4 =100
E/4 + 6E = 100
(E + 24E)/4 = 100
25E = 4 x 100
E = 4 x 4
Therefore we get the value of E as;
E = 16
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Answer: 16
A×4 = E, so A = E/4
B/4 = E, so B = 4E
C+4 = E, so C = E-4
D-4 = E, so D = E+4
and
A+B+C+D=100.
now substitute the values that we got of A, B, C and D in the equation, to get,
(E/4) + 4E + E-4 + E+4 = 100
(E/4) + 4E + 2E = 100
(E/4) + 6E = 100
(E+24E)/4 = 100
E+24E = 100×4
25E = 400
E = 400/25
E = 16