Look at the series of equations and find the connection between the letters.
Find the missing letters in the last equation;
If;
A = B
B = J
C = Z + D
D = Z + Z + P
Then;
E = ???
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As you must have already figured out, we need to first substitute the letters with numbers.
Say A = 1, B = 2, C = 3…….. Z =26
Find the table below;
| A | B | C | D | E | F | G | H | I | J | K | L | M | N | O | P | Q | R | S | T | U | V | W | X | Y | Z |
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 | 25 | 26 |
After noticing the equation you will find out that they follow the pattern below;
A = 1 = 2 (1^3 + 1= 2)
B = 2 = 10 (2^3 + 2= 10)
C = 3 = 30 (3^3 + 3= 30)
D = 4 = 68 (4^3 + 4= 68)
Therefore we can find the missing number as;
5 = 130 (5^3 + 5 = 130)
The value 130 is;
130/26 = 5 so five times Z
Answer = Z + Z + Z + Z + Z
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