Here’s a fun math riddle for you to solve.
Let’s get your imagination wild…here are some unreal creatures trapped in a bag.
Read the hints and answer the question.
An Octopulus has 8 legs.
A Septapuslus has 6 legs and 2 pairs of wings.
A Spanepulus has 6 legs and one pair of wings.
Now we have all 3 kinds and a total of 18 creatures in a cage.
We have a total of 118 legs and 20 pairs of wings.
How many creatures do we have of each kind?
So were you able to solve the riddle? Leave your answers in the comment section below.
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Answer:
Let ‘A’ be the number of Octopulus, ‘B’ be number of Septapuslus and ‘C’ be number of Spanepulus.
A + B + C = 18………….. (1)
8A + 6B + 6C = 118….. (2)
2B + C = 20………………. (3)
Solving this 3 equations,
Rewriting (1)
B + C = 18 – A…………… (4)
Rewriting (2)
8A + 6(B + C) = 118
Therefore;
B + C = (118 – 8A)/6 …..(5)
From (4) and (5);
18 – A = (118 – 8A)/6
108 – 6A = 118 – 8A
Therefore;
2A = 118 – 108 = 10
Therefore;
A = 5.
Substituting value of A in (4)
B + C = 18 – 5 = 13
Rewriting (3)
B + (B + C) = 20
B + 13 = 20
Therefore;
B = 7
Substituting value of B and A in (1)
A + B + C = 18
5 + 7 + C = 18
Therefore;
C = 6
Answer: A=5, B=7, C=6
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